ASSIGNMENT 2
Rankine Cycle
Group 3
Parametric Study of the Rankine Cycle
1 Analysis of the problem: Find the thermal efficiency of the cycle (assume isentropic efficiency of the turbine to be 92%)
2 Tablulation calculation in EXCEL, varying the PARAMETER
3 Plot graph show the relation of the study parameter vs. the cycle thermal efficiency
4 Show on your group website
Process
1 - 2 s= constant + WT
2 - 3 P = const. - qL
3 - 4 s= constant - Wp
4 - 1 P = const. +qH
Cycle efficiency = Wnet/qH
Wnet = WT-Wp = qH - qL
Isentropic efficiency = Wa / Ws = (h1-h2)/(h1-h2s)
Case 1
Variable Value unit
BOILER PRESSUREBegin 4 MPa
BOILER PRESSUREEnd 10 MPa
Steam temperature 350 oC
Condenser Pressure 10 kPa
State 1 Turbine
T1 = 350 oC Superheate water
P1 = 4-10 Mpa
isentropic s1=s2
S1 @ T1,P1 Superheat water
h1 @ T1,P1 Superheated water from Table A-6
1st Law, q=o WT=h1-h2
P1 = 4-10 Mpa
isentropic s1=s2
S1 @ T1,P1 Superheat water
h1 @ T1,P1 Superheated water from Table A-6
1st Law, q=o WT=h1-h2
State 2 Condensor Mixture water
P2 =P3 const 10 kPa
s1=s2
sf, sfg,hf,hfg @ P2 to find x2,h2
s=sf+ xsfg h = hf +xhfg
1st Law, W = 0 qc = h3-h2
1st Law, W = 0 qc = h3-h2
State 3 Pump Sat.liquid
P2 =P3 const 10 kPa
h3 = hf @ 10kPa 191.83 kJ/kg
v=v3 = const = vf @ P3
1st Law q=0; Wp = h3 - h4 = v(P3-P4)
h3 = hf @ 10kPa 191.83 kJ/kg
v=v3 = const = vf @ P3
1st Law q=0; Wp = h3 - h4 = v(P3-P4)
State 4 Boiler
4=P1 4-10 Mpa
h4 = h3 + Wp
1st Law W=0; qB = h1-h4
h4 = h3 + Wp
1st Law W=0; qB = h1-h4
ผลการคำนวณค่าต่าง ด้วย โปรแกรม Excel
จากกราฟ เมื่อแกน y คือค่า Thermal efficiency และ แกน x คือ Boiler
Pressureจะเห็นได้ว่า เมื่อเพิ่ม ค่า Boiler Pressure จาก 4 MPa ไปจนถึง 10 MPa จะทำให้ค่าThermal efficiency เพิ่มขึ้น